Chemistry Electrochemical cells lab. Need help filling out the columns please!!!

Question

Chemistry Electrochemical cells lab. Need help filling out the columns please!!!

Table 1: Electrochemical Cell Potentials Individual Half-Cell Potentials Measured Total Metal Cell Potential from (Cu) Electrode Metal Electrode Electrode Electrode Experimental Theoretical Potential % Error Cell Reactions G (k) Multimeter (vr l Potential (vy potential(w Potential(VEL er (VStandard Cathode: Anode: Net: Cathode Cu | Sn .465 CuA ,050 Cu l Fe .55 CulZn 1.045 0.34 V 0.34 V Anode: Net Cathode: Anode: Net: Cathode Anode: 0.34 V 0.34 V Net: Your reading that you took using your multimeter during the experiment The standard reduction potential for Cu taken from a standard reduction table like the one below. The formula for copper gluconate is Cu/CeHO,S the reaction here involves Cu ions. The total potential that you measured is actually the voltage difference between the cathode and the anode (each half-cell). Since you are using Cu as the cathode in each cell (it is constant), you will use it as your standard by which to determine the half-cell potential of the other metals at the anode Total (V) - Cathode (V)- Anode (V). Therefore, Anode (V) Cathode (V)- Total (V). In other words, subtract your multimeter reading from 0.34 V to find the experimental potential of your anode. Taken from a standard reduction table (see below). Pay attention to the chemical formulas given in the materials section above so that you select the correct reaction. Write the reaction occurring at each electrode, then combine them into a balanced net equation for the entire voltaic cell. aG -nFE (remember that in this equation, E, or voltage, is for the entire cell) Percent Error Calculations (label each cell clearly and do the math in the electrode order indicated in the table): AG Calculations (label each cell clearly and do the math in the electrode order indicated in the table)

Explanation / Answer

E°Cell = E°cathode - E°anode . Cathode means redution .and anode means oxidation .but in this reduction potential is taken in both case cathode and anode .now put the vale value give in table .we calculate the Ecell. Now the acording to Nearnest equation .we calculate the single electrode potential by applying nernst equation .

Ecell = E°cell -0.0591/n log [oxidise ]/[reduced]

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