The presences of the radioactive gas radon (Rn) in well water presented a possib

Question

The presences of the radioactive gas radon (Rn) in well water presented a possible health hazard in the parts of the United States. a) Assuming that the solubility of radon in water in equilibrium with 1 atm of radon pressure is 7.27E-3 M at 30*C, what water at this temperature? b) A sample consisting of a variety of gases including radon is equilibrated with water at 30°C. The mole fraction of radon in the mixture is 3.5E-6, and the total pressure of the gas is 32 atm. Calculate the molar concentration of radon in the water. 2. is the Henry's Law constant for radon irn

Explanation / Answer

2. By using Henry's laaw,

a) SRn = kPRn

         k =7.27*10-3 M/1atm

            = 7.27*10-3 M/atm

b) First calculate the partial pressure of Rn

    PRn = RnPT

   Where PT is the total pressure =32atm

    mole fraction of Rn =3.5x10-6

      PRn =3.5x10-6 * 32atm = 1.12*10-4atm

      Now u have to calculate molarconc of Rn that is SRn

    SRn = kPRn

           =7.27*10-3 M/atm * 1.12*10-4atm

          =8.14*10-7M

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