31) To extend a length of 1.00 inches, 2.54 x 10 8 average sized atoms would hav

Question

31) To extend a length of 1.00 inches, 2.54 x 10 8 average sized atoms would have to be placed in a straight line (in other words, 2.54 x 10 8 atoms per 1.00 inches). How many averaged sized atoms, placed in a straight line, would be required to form a line extending from the Earth to the moon when the moon is its farthest distance from the Earth? When the Earth and the moon are as far apart from each other as they ever get, the distance between the two is 405,696 km. (YOU MUST SHOW YOUR WORK ON ATTACHED SHEETS) PLACE ANSWER HERE

Explanation / Answer

there are 2.54*108 atoms/ inch

12 inches = 1 ft, 1ft =0.3048 m

1inches= 1/12 ft= (1/12)*0.3048 m =0.0254 m

0.0254 m contains 2.54*108atoms, there are 405696 km=405696*1000m= 4.06*108 m

4.06*108 m contains 4.06*108*2.54*108/0.0254 atoms=4.06*1018 atoms

distance required =405696 km,

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