The following results were obtained when a sample of mango juice was analyzed to

Question

The following results were obtained when a sample of mango juice was analyzed to determine its vitamin C content. A 40.0 mL sample of the juice was placed in a flask with 20 ml of 0.5 M H,SO,,2.0g of potassium iodide, KI, and 40.00 mL of 0.02912 M potassium iodate, KIO, Titration with sodium thiosulfate required the use of 32.81 mL of 0.1255 M NaS,O,.Calculate the concentration of vitamin C in the juice sample in mg vitamin C per 100 ml, juice. Parts a - e below take you through this calculation step by step. 3. a. How many total millimoles of I, are produced from the reaction between KI and KIO,? b. How many millimoles of I, are consumed from the reaction with thiosulfate ion? c. How many millimoles of I, reacted with the ascorbic acid in the juice? d. How many milligrams of ascorbic acid were in the juice sample? -1.975 mmol#176r -346.97 What is the concentration of Vitamin C in the juice sample expressed as mg Vitamin C per 100 mL of juice? e.

Explanation / Answer

A. Yes it is correct as molecular mass of KI is 166g.

D. Correct as molecular mass of ascorbic acid is 176.12g/mol

So mass of acid will be equal to (no of moles*molecular mass)

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