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owLv2 | Online teachin-X + -> O | sjc.cengagenow.com/iln/takeAssig entActivity.d

ID: 573027 • Letter: O

Question

owLv2 | Online teachin-X + -> O | sjc.cengagenow.com/iln/takeAssig entActivity.do?locator= assignment ignmentSessionLocator= assignment-take Chapter 10: Mastery 1. Compare Absolute Entroples 2. Predict the Sign of AS Use the References to access important values if needed for this question. For the reaction 1 pts 2req 1 pts 2req 1 pts 2red 1 pts 2req 7 Enthalpy. Entropy and Temper-ptsp 8, G: Calculate Temperature Limit 1 pts 2req HCl(g) +NH3(gNH4CI(s) 4. Standard Entropy of Reaction Go would be negative at temperatures (above, below) K. 6. AG: Predict Signs Enter above or below in the first box and enter the temperature in the second box. Assume that H° and S° are constant. Subnit Answer Retry Entire Group 8 more group attempts remaining Question Question s of Refining Met pts 2req 10. AG from Free Energies of Form pts 2req

Explanation / Answer

deltaH = -176.0 KJ/mol

deltaS = -285 J/mol.K

= -0.285 KJ/mol.K

we have below equation to be used:

deltaG = deltaH - T*deltaS

for reaction to be spontaneous, deltaG should be negative

that is deltaG<0

since deltaG = deltaH - T*deltaS

so, deltaH - T*deltaS < 0

-176.0- T *-0.285 < 0

T *0.285 < 176.0

T < 618 K

Answer: below 618 K