for my chem2 lab class we preformed a nut combustion experiment to get the calor
ID: 573126 • Letter: F
Question
for my chem2 lab class we preformed a nut combustion experiment to get the calorie count in different kinds of nuts. for my post lab questions i was asked to use my results to answer this question and i have no idea how to set it up:
based on your energy determined of the first nut that you burned, determine how many nuts an average man of 68kg would have to eat in order to swim 30mins. (energy burned by an average man of 50kg per hour of swimming is 553 Cal/kg)
for my results showed that my first nut showed for the trial 2.55Cal/g
Explanation / Answer
Energy burned in 30 min swimming for average man of weight 68 Kg =
553 Cal/50 Kg.hr * 68Kg * 1 hr/60 min * 30 min = 553 * 68/50 * 1/2 = 376.04 Cal
Energy of a single nut = 2.55 Cal/g
Number of nuts required to approximate the energy = Number of calories burned in swimming/number of calories in nuts
=> 376.04/2.55
=> 147.466 grams of nuts
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