The Van\'t Hoff Factor The way we account for salts such as KBr dissolving into

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The Van't Hoff Factor The way we account for salts such as KBr dissolving into multiple particles per mole of salt is by applying a "correction factor" to the concentration calculations we perform. This is referred to as the van't Hoff factor, and is abbreviated i particles in solution moles of formula units dissolvec For the purposes of this course, you can assume i is equal to the number of particles any compound breaks into when it dissolves into a solution. For KBr and Sr(NO3)2, i would equal 2 and 3 respectively. However, in reality i can deviate from this ideal, which may cause actual freezing and boiling points to deviate from what they are calculated to be. Keep this in mind when you analyze your results. When you look at a chemical formula to determine how many particles a compound will yield per mole, you may see a notation on the formula that looks like “XH20", where X could be any number. This notation indicates the salt is hydrated, meaning its got water molecules stuck to it. These water molecules are not included in the number of particles per mole. Thus, a salt with the formula "MgS-4H20" would only yield 2 particles per mole (just the Mg and the S).

Explanation / Answer

First thing you wrote the wing formula of sodium sulfate.

It is Na2SO4.10H2O

Now as stated in the second paragraph that the H2O moles will not be count in van't hoff factor.

So when the compound is hydrated, it will dissociate in 2 Na+ and 1 SO4-2 so the van't hoff factor here is i=3.

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