nt/takeCovalentActivity do?locator-assignment-take&takeAssignmentsessionL.ocator

Question

nt/takeCovalentActivity do?locator-assignment-take&takeAssignmentsessionL.ocator-; assignment take Use the Refereaces to access important valses if aeeded for thi question compound is found to contain 37.23 % carbon , 7.827 % hydrogen, and 54.94 % chlorine by mass. o answer the question, enter the elements in the order presented above. UESTION 1: The empirical formula for this compound is QUESTION 2 The molar mass for this compound is 64.52 g/mol. The molecular formula for this compound is Sabnt Answer Retry Entire Group 9 more group attempts remaining

Explanation / Answer

mass of carbon = 37.23 g

moles of Carbon = 37.23 / 12 = 3.1025

moles of Hydrogen = 7.827 / 1 = 7.827

moles of Chlorine = 54.94 / 35.5 = 1.55

mol ratios :

      C          H              Cl

3.1025     7.827         1.55

    2             5                1

Emperical formula = C2H5Cl

mass of emperical formula = 64.5 g

molecular mass = 64.52 g

n = 64.5 / 64.5 = 1

Molecular formula = n x emperical formula

Molecular formula = C2H5Cl

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.