a) A 105 g slab of metal is dropped into a cylinder which has 69.9 mL of water i
ID: 573990 • Letter: A
Question
a) A 105 g slab of metal is dropped into a cylinder which has 69.9 mL of water in it. The water goes up to 83.3 mL with the metal slab in it. What is the density and identity of the metal? First calculate the volume considering the water displacement data provided. Then solve for density.
b) convert the volume of this metal to cm3
c) This part follows the above two parts about the slab of metal. This slab of metal was actually a cylinder with a 0.60 cm radius, how tall is the cylinder? To calculate this, consider the volume you calculated above. Use the formula V=r2h
Explanation / Answer
a)
mass of slab = 105 g
volume of water in cylinder = 69.9 mL
volume of water rise = 83.3 mL
volume of metal = 83.3 - 69.9 = 13.4 mL
density = mass / volume
= 105 / 13.4
density of metal = 7.84 g /mL
b )
density of metal = 13.4 cm3
c)
volume = r2h
13.4 = 3.14 x (0.60)^2 x h
h = 11.8
height of cylinder = 11.8 cm
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