Basic solution Potassium permanganate, KMnO4, is a powerful oxidizing agent. The

Question

Basic solution Potassium permanganate, KMnO4, is a powerful oxidizing agent. The products of a given redox reaction with the permanganate ion depend on the reaction conditions used. In basic solution, the following equation represents the reaction of this ion with a solution containing sodium sulfite: MnO4(aq)+SO32(aq)MnO2(s)+SO42(aq) Since this reaction takes place in basic solution, H2O(l) and OH(aq) will be shown in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: MnO4(aq)+SO32(aq)+ MnO2(s)+SO42(aq)+ Part B What are the coefficients of the six species in the balanced equation above? Remember to include coefficients for H2O(l) and OH(aq) in the blanks where appropriate. Enter the equation coefficients in order separated by commas (e.g., 2,2,1,4,4,3).

Explanation / Answer

Ans

Part A :

Since the reaction takes place in the basic medium , the OH- is used to balance the H+ present in the reaction while balancing out.

So H2O (l) will be placed in reactants side and OH- (aq) in products side.

So in the reaction :

MnO4- (aq) + SO32- (aq) + H2O (l) = MnO2 (s) + SO42- (aq) + OH-

Part B :

Start balancing the reaction by seperating it into oxidation and reduction half reactions.

Then balance all other atoms except H and O.

balance H and O by adding protons and water molecules respectively.

balance the protons by adding OH- on both the sides.

Add the reactions together and simplify to get the final reaction as :

2MnO4- + 3SO32- + H2O = 2MnO2 + 3SO42- + 2OH-

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