You have infected E.coli cells with two strains of T4 bacteriophage. One strain

Question

You have infected E.coli cells with two strains of T4 bacteriophage. One strain is minute(m)m rapid lysis(r) and turbid(tu); the other is wild type for all 3 markers. the lytic products of this infections areplated and classified. The resulting 10351 plaques were distributed among eight genotypes as follows

A) what is the order of these genes in the T4 genome ?

B) what are the genetic distances between them ?

C) How much interfernce is there?

m r tu 3600 + + + 3800 m r + 852 m + + 519 m + tu 75 + + tu 965 + r + 70 + r tu 470

Explanation / Answer

Frequency of minute (m) = 3600 + 852 + 519 + 75 = 0.487

Frequency of rapid lysis (r) = 3600 + 852 + 70 + 470 = 0.482

Frequency of turbid (tu) = 3600 + 75 + 965 + 470 = 0.493

The order of genes = rapid lysis (r) - minute (m) - turbid (tu) or (r - m - tu)

The distance between r and m = 0.487 - 0.482 = 0.05 m.u

The distance between m and tu = 0.493 - 0.487 = 0.06 m.u

The distance between r and tu = 0.493 - 0.482 = 0.011 m.u

recombinants between r and m = 3600 + 852 = 0.43

Recombinants between r and tu = 3600 + 470 = 0.39

Coefficient of Coincidence between r and m = 0.05/ 0.43 = 0.116

Coefficient of coincidence between r and tu = 0.011/ 0.39 = 0.028

Interference between r and m = 1 - 0.116 = 0.884

Interference between r and tu = 1 - 0.028 = 0.972

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