Print E Calculator-d Periodic Table Question 21 of 24 Map ds General Chemistry 4

Question

Print E Calculator-d Periodic Table Question 21 of 24 Map ds General Chemistry 4th Edition University Science Books presented by Sapling Leaming 20.0-g ice cubes at-100°C are placed into 285 g of water at 25.0 . Assuming no energy is ransferred to or from the surroundings, calculate the final temperature, Tr, of the water after all the ice melts. heat capacity of H20(s) 37.7(mol-K) heat capacity of H2O()75.3 J(mol K) enthalpy of fusion of H20 6.01 kJ/mol Number T12.95 O Previous Give Up & View Solution O Check Answer ) Next - Exit Hint

Explanation / Answer

mass of ice = 2 x 20 = 40 g

moles of ice = 40 / 18.02 = 2.22 mol

Q1 = m Cp dT

     = 2.22 x 37.7 x 10

     = -836.85 J

Q2 = 2.22 x 6.01 x 10^3

      = -13342.2 J

Q3 = 2.22 x 75.3 x 25

      = -4179.15 J

total heat = Q1 + Q2 + Q3

                = -18358.2 J

Q = m Cp dT

moles of water = 40 + 285 / 18.02 = 18.036

- 18358.2 = 18.036 x 75.3 x (Tf - 25)

Tf = 11.5 oC

final temperature = 11.5 oC

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