A detailed answer of all steps would be very appreciated! Map Sapling Learning m
ID: 576829 • Letter: A
Question
A detailed answer of all steps would be very appreciated!
Map Sapling Learning macmillan learning If you were going to graphically determine the activation energy of this reaction, what points would you plot? Consider this reaction data A products Number Number T (K) k (s) 275 525 point 1 To avoid rounding errors, use at least hree signiticant figures in all values 0.385 0.664 Number Number point 2 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number What is the activation energy of this reaction? Number J/ molExplanation / Answer
We need to plot lnK on y axis and 1/T on x axis
k = 0.385
ln k = ln (0.385) = -0.95451
T = 225.0
1/T = 0.00444
point 1 is:
x = 0.00444
y = -0.95451
k = 0.664
ln k = ln (0.664) = -0.40947
T = 525.0
1/T = 0.0019
point 2 is:
x = 0.0019
y = -0.40947
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rise = (y1-y2) = -0.95451 - -0.40947 = -0.54504
rise = (X1-X2) = 0.00444 - 0.0019 = 0.00254
slope = rise/run
= -0.54504/0.00254
= -214.60903
----------------------------------------------------------------------------
use
slope = - Ea/R
= -214.60903 = -Ea/8.314
Ea = 1784 J/mol
Answer: 1784 J/mol
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