× This Lab Is About Determin. | + t-content rid 8243657 3/orgs/11FA,CHEM124 Labs

Question

× This Lab Is About Determin. | + t-content rid 8243657 3/orgs/11FA,CHEM124 Labs/Exp%20%2010%20 bility%20 roduct%20Lab%20Ch Standard 1.0-1 M Standard 2 5.0E-2 Standard 32-2M Standard 4 1E-2 Standard S SE-3 troscopy Data Absorbance Standard 1 1.166 Stendard 2546 Standard 3 Standard 4 100 Standard 036 Saturated Solution342 Value Slope of trendline for Calibration Curve 11.823 Intercept of trendline for Calibration Curve0251 Con Con Value Value of cb 11.823Co Value Inc Concentration of copper in saturated solutio Value Value of Kso for Copper (II) tartrate Value [Cu) in solution M Inc

Explanation / Answer

(3)

Given calibration equation:

A = 11.823*C + 0.0251

Absorbance of saturated solution = 0.342

Putting this value in the above relation:

0.342 = 11.823*C + 0.0251

So,

Conc of Copper in the saturated solution = C = 0.0268 M

(4)

The Ksp expression for copper tartrate is:

Ksp = [Cu2+]*[C2H2O62-]

Also,

[Cu2+] = [C2H2O62-]

So,

Ksp = 0.0268^2 = 0.000718 M2

(5)

Final volume after mixing = 20 mL

So, conc of tartrate ions in the final mixture = 1/2 = 0.5 M

Using the Ksp expression:

Ksp = [Cu2+]*[C2H2O62-] = 0.000718

Putting value:

[C2H2O62-] = 0.5 M

So,

[Cu2+] = 0.000718/0.5 = 0.00144 M

Hope this helps !

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