UNITI\" End of Chapter Practice ssignment can be completed outside of class and
ID: 577623 • Letter: U
Question
UNITI" End of Chapter Practice ssignment can be completed outside of class and counts towards a maximum of 3% towards your final grade. When completing each problem, you must show all of your answer is worth lit handwritten i will result in an automatic deduction of 50%. Late assignments will not be a work for full marks. The final tl e in comparison to the details of your work. This assignment must be submitted and n INK by the indicated due date. Assignments that are completed using a word processor 0 marks. ccepted and you will receive 1. At 1000 K, Kp = 1.85 for the reaction: SO2 (g) + ½ O2 (g) so, (g) (a) what is the value of Kp for the reaction: SO3 (g) so2 (g) + ½ O2 (g) (b) what is the value of K, for the reaction 2 S0; (g) + O2 (g) 2 SO3 (g) (c) What is the value of K for the reaction in part B The following equilibria were attained at 823 K: CoO(s) + H2(g) Co(s) + H2O (g) Kc-67 CoO(s) + CO(g) Co(s) +CO2(g) K.-490 Based on the above, what is the Kc for: H2(g) + CO2(g) CO(g) + H2O(g) at the same temperature 2. A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 101 300 K. The following equilibrium is established 3. 2 NO (g) + 2 H2 (g) N2 (g) + 2 H2O (g) At equilibrium [NO] 0.062 M. (a) Calculate the equilibrium concentrations of H2, (b) Calculate Kc 4. At 2000 C the equilibrium constant for the reactionExplanation / Answer
Ans 1 :
a) The reaction SO3 = SO2 + 1/2O2 , is reverse of the actual reaction.
So the kp is given as : 1 / 1.85
= 0.54
b) The reaction 2SO2 + O2 = 2SO3 , is exactly double of the original reaction.
So kp will be given as : (1.85)2
= 3.4225
c) kc = kp / (RT)n
where n is change in number of moles = -1
kc = 3.4225 / (0.0831 x 1000)-1
kc = 284.4
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