Please help me answer this question. It is a physical chemistry question that is

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Please help me answer this question. It is a physical chemistry question that is due in a few hours, so I need the help of a physical chemistry expert. I really need help with these questions for my hw grades. Any help would be appreciated.

Homework 16. Due Tuesday November 21 Given below is the graph from the analysis of vapor pressure vs. Temperature for water. I have plotted the x axis as I/T rather than 1000/T because the factor of 1000 makes evaluating the derivative complicated Clausius-Clapyeron fit to water's vapor pressure 45 y '241 782x2-3682·3x + 16.222 3.5 25 Poly. (lata 05 00025 0.0027 00029 00031 00033 0.0035 0.0037 0.0039 1/T Using the differential form of the Clausius Clapeyron equation, determine the enthalpy of vaporization at 298 K and at 373.15 K. Compare these values with the literature values found in our text calculating the percentage deviation from those values

Explanation / Answer

Recall that in equilibrium; especially in vapor-liquid equilibriums, we can use Clasius Clapyeron combination equation in order to relate two points in the same equilibrium line.

The equation is given as:

ln(P2/P1) = -dHvap/R*(1/T2-1/T1)

Where

P2,P1 = vapor pressure at point 1 and 2

dH = Enthalpy of vaporization, typically reported in kJ/mol, but we need to use J/mol

R = 8.314 J/mol K

T1,T2 = Saturation temperature at point 1 and 2

Therefore, we need at least 4 variables in order to solve this.

Substitute all known data:

ln(P2/P1) = -dHvap/R*(1/T2-1/T1)

then

from your data

slope = -Hvap/R

slope = -2417.82

Hvap= - R*-2417.82

Hvap = 8.314*2417.82

Hvap = 20101.75J/mol

HVap = 20.1 kJ/mol

Hvap is considered constant,. then Hvap(298) = Hvap(373.15)

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