Digital Resources for Chemist X 11 ALE KS-Roese Weslow-Les x (G barium nitrate m

Question

Digital Resources for Chemist X 11 ALE KS-Roese Weslow-Les x (G barium nitrate molar mass-G × Secure l https://www.awh.a sl.exe/1o u-IgNslkr78P3 H-IQ1hQv-T2 6Ux63S Reese Solving limiting reactant problems in solution Suppose 15.3 g of sodium chloride is dissolved in 150. ml. of a 0.60M aqueous solution of siliver nitrate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the sodium chloride is dissolved in it. Round your answer to 3 significant digits.

Explanation / Answer

Mass of sodium chloride = 58g/mole

Now 58 grams contains 35.5 grams chlorine

1 gram contains 35.5/58

15.3 grams contains (35.5/58.5)*15.3

= 9.28 grams

Now moles = 9.28/35.5

= 0.2614

Here moles of silver in silver nitrate

150*0.6 )/1000 = 0.09 here it will form precipitation of agcl

0.09 agcl will form

Remaining = 0.2614-0.09

= 0.1714 mole

MOLARITY = 0.1714/0.150

1.1427 M

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