Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Have 1.00 G Sample www.saplinglearningcor ×y.. Arkansas Tech University xYChemis

ID: 579524 • Letter: H

Question

Have 1.00 G Sample www.saplinglearningcor ×y.. Arkansas Tech University xYChemistry. Identify pla × om/ibiscms/mod/ibis/view.php?id-5113616 niversity -CHEM 2124-Spring18-GAJEWSKIActivities and Due Dates HW 2 2/7/2018 11:59 PM 69.5/1002/6/2018 11:36 PM Print Calculator Periodic Table uestion 4 of 31 Sapling Learning Maj Suppose there are two known compounds sample of each compound. One sample contains 0.30 g of X and the other contains 0.39 gof X the ic elements X and Y. You have a 1.00-g identify plausible sets of formulas for these two compounds. Check all that apply XY3 and XY4 X2Y4 and X3Y4 O Previous Give Up & View Solution Check Answer 0 Next Exit

Explanation / Answer

Given that mass of each sample = 1.0 g

1st sample:

mass of X = 0.3 g

Hence,

mass of Y = 1.0 g - 0.3 g = 0.7 g

2nd sample:

mass of X = 0.39 g

Hence,

mass of Y = 1.0 g - 0.39 g = 0.61 g

Ratio of ratios of two samples:

(Y/X) of 1st sample/ (Y/X) of 2nd sample = (0.7/0.3) / (0.61/0.39) = 1.5

Check the ratio of ratios of all choices:

1) XY3 and XY4

= (3/1) / (4/1) = 0.75 = NO

2) X4Y2 and X3Y

= (2/4) / (1/3) = 1.5 =YES

3) XY and X2Y

= (1/1)/ (1/2) = 2 = NO

4) X3Y and X4Y

= (1/3) / (1/4) = 1.33 = NO

5) X2Y and X3Y

= (1/2)/ (1/3) = 1.5 = YES

6) XY and X3Y

= (1/1) (1/3) = 3 = NO

7) X2Y4 and X3Y4

= (4/2)/ (4/3) = 1.5 = YES

----------------------------------------------

Therefore,

Plausible set of formulas of two compounds are

X4Y2 and X3Y

X2Y and X3Y

X2Y4 and X3Y4

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote