Please need help with this expressions I cant see real good please print 1) The

Question

Please need help with this expressions I cant see real good please print

1) The water dissociation constant expression

Kw = [     ][      ] = ?

Also, Please need help with this graph I cant see real good please print

Thank you

2.) For each condition mark if the Ka is large or small

Condition

Ka large

Ka small

Weak acid

Strong acid

Equilibrium toward reactants

Equilibrium toward products

Weak conjugate base

Strong conjugate base

100 % [HA] dissociates

Small % [HA] dissociates

Condition

Ka large

Ka small

Weak acid

Strong acid

Equilibrium toward reactants

Equilibrium toward products

Weak conjugate base

Strong conjugate base

100 % [HA] dissociates

Small % [HA] dissociates

Explanation / Answer

In order to be able to calculate pH, pOH and [H3O+]/[H+] and [OH-] we must understand the relationship between each of them

Remember that water will ionize as follows:

H2O(l) + H2O(l) <-> H3O+(aq) + OH-(aq)

so

Kw = [H3O+][OH-]

at T = 25°C, the Kw value is given as 10^-14

then,

10^-14 = [H3O+][OH-]

can be used always to relate H3O+ and OH-

also, note that

pH = -log([H+])

pOH = -log([OH-])

and

pH + pOH = 14 (stated above)

Q2

conditions / KA large / Ka small

weak acid = Ka small

Strong acid = Ka large

equilibirum favours reactants --> Ksmall

equilibirum favours products--> large

Weak conjguate base --> strong acids --> Ka large

strong  conjguate base --> Weak acids --> Ka Ksmall

100% ionization --> strong acids --> Ka large

small % ionization -> Weak acids --> Ka Ksmall

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