Use the half-reaction method to balance each redox reaction occurring in acidic

Question

Use the half-reaction method to balance each redox reaction occurring in acidic aqueous solution.

Part A

PbO2(s)+I(aq)Pb2+(aq)+I2(s)

Express your answer as a chemical equation. Identify all of the phases in your answer.

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Part B

SO32(aq)+MnO4(aq)SO42(aq)+Mn2+(aq)

Express your answer as a chemical equation. Identify all of the phases in your answer.

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Part C

S2O32(aq)+Cl2(g)SO42(aq)+Cl(aq)

Express your answer as a chemical equation. Identify all of the phases in your answer.

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Use the half-reaction method to balance each redox reaction occurring in acidic aqueous solution.

Part A

PbO2(s)+I(aq)Pb2+(aq)+I2(s)

Express your answer as a chemical equation. Identify all of the phases in your answer.

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Part B

SO32(aq)+MnO4(aq)SO42(aq)+Mn2+(aq)

Express your answer as a chemical equation. Identify all of the phases in your answer.

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Part C

S2O32(aq)+Cl2(g)SO42(aq)+Cl(aq)

Express your answer as a chemical equation. Identify all of the phases in your answer.

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Explanation / Answer

A)

PbO2(s)+I(aq)Pb2+(aq)+I2(s)

split

PbO2 = Pb+2

I- = I2

balance

PbO2 = Pb+2

2I- = I2

add H2O

PbO2 = Pb+2 + 2H2O

2I- = I2

add H

4H+ + PbO2 = Pb+2 + 2H2O

2I- = I2

balance charge

2e- + 4H+ + PbO2 = Pb+2 + 2H2O

2I- = I2 + 2e-

balance and add all

2I- + 2e- + 4H+ + PbO2 = Pb+2 + 2H2O + I2 + 2e-

cancel common terms

2I- +4H+ + PbO2 = Pb+2 + 2H2O + I2

add phases

2I-(aq) +4H+(aq) + PbO2(s) = Pb+2(aq) + 2H2O(l) + I2(s)

Q2.

SO32(aq)+MnO4(aq)SO42(aq)+Mn2+(aq)

split

SO3-2 = SO4-2

MnO4- = Mn+2

balance O

H2O + SO3-2 = SO4-2

MnO4- = Mn+2 + 4H2O

balance H

H2O + SO3-2 = SO4-2 + 2H+

8H+ + MnO4- = Mn+2 + 4H2O

balance charge

H2O + SO3-2 = SO4-2 + 2H+ + 2e-

5e- + 8H+ + MnO4- = Mn+2 + 4H2O

balanc e-

5H2O + 5SO3-2 = 5SO4-2 + 10H+ + 10e-

10e- + 16H+ + 2MnO4- = 2Mn+2 + 8H2O

add all

10e- + 16H+ + 2MnO4- + 5H2O + 5SO3-2 = 5SO4-2 + 10H+ + 10e- +  2Mn+2 + 8H2O

simplify

6H+ + 2MnO4- + 5SO3-2 = 5SO4-2 + 2Mn+2 + 3H2O

add phases

6H+(aq) + 2MnO4-(aq) + 5SO3-2(aq) = 5SO4-2(aq) + 2Mn+2(aq) + 3H2O(l)

c)

S2O32(aq)+Cl2(g)SO42(aq)+Cl(aq)

S2O3-2 = SO4-2

Cl2 = Cl-

balance

S2O3-2 = 2SO4-2

Cl2 = 2Cl-

balance O

2H2O + S2O3-2 = 2SO4-2

Cl2 = 2Cl-

balance H

2H2O + S2O3-2 = 2SO4-2 + 4H+

Cl2 = 2Cl-

balance charge

2H2O + S2O3-2 = 2SO4-2 + 4H+ + 2e-

2e- + Cl2 = 2Cl-

add all

2e- + Cl2 + 2H2O + S2O3-2 = 2SO4-2 + 4H+ + 2e- + 2Cl-

simplify

Cl2 + 2H2O + S2O3-2 = 2SO4-2 + 4H+ + 2Cl-

add phases

Cl2(aq) + 2H2O(l) + S2O3-2(aq) = 2SO4-2(aq) + 4H+(aq) + 2Cl-(aq)

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