0/10 points ! Previous Answers Harrischem7 24P20. My Notes A standard solution c

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0/10 points ! Previous Answers Harrischem7 24P20. My Notes A standard solution containing 5.9 × 10 8 Miodoacetone and 2.3 x 10-7 M p dichlorobenzene an internal standard gave peak areas of 353 and 877, respectively, in a gas chromatogram. A 3.00 mL unknown solution of iodoacetone was treated with 0.100 mL of 9.0 10-6 M p-dichlorobenzene and the mixture was diluted to 10.00 mL. Gas chromatography gave peak areas of 894 and 451 for iodoacetone and p-dichlorobenzene, respectively. Find the concentration of iodoacetone in the 3.00 mL of original unknown 49 .50

Explanation / Answer

In the unknown prep, the concentration of internal standard (IS) is calculated as follows:

(0.1ml)(9.0 × 10-6M) = (3.1ml)(xM) and x= 2.903 × 10-7

This is then diluted to 10mls, so conc. of I.S is

(3.1ml)(2.903 × 10-7M) =(10ml)(xM)

x=9.0 ×10-8M

This would be the final conc. of IS in the 10ml of diluted unknown.

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