Two of my answers on this fill in the blank, are incorrect. There is a similar q

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Two of my answers on this fill in the blank, are incorrect. There is a similar question posted on Chegg, but the author of that answer was very incorrect, so please no copy paste action. Only answer if you understand it and can explain it, so I can rate you well. Thank you!

Reset Help faster The helium atoms are 5 times lighter than the neon atoms, they are traveling, on average, V5 times faster than the neon atoms. times faster) than th greater verage smaller Since the momentum depends on the velocity and mass, the momentum of the helium atoms is momentum of the neon a -m-m | v/5 | times smaller than the toms slower V5 Finally, since the helium atoms travel faster, they collide more often, again by the factor of 5 Summarizing this facts we see that the helium atoms collide with the walls | 5 | times more often, but each collision is times weaker Consequently, the pressures exerted by the two different gases are the same. You filled in 2 of 6 blanks incorrectly

Explanation / Answer

here,
Atomic mass of helium , mh = 2
Atomic mass of Neon, mn = 20

Velocity of an atom in gas at some temperature T si given as,
V = sqrt(k*T/3m) ---------------(1)

Where,
k = Boltzman constant
T = Temperature
m = mass in one mole

Rewriting Equation 1 as,

Vh = sqrt(k*T/3mh) ------------(2)
Vn = sqrt(k*T/3mn) ------------(3)

Vn = sqrt(k*T/3*20) (Compaing this with eqn 2 using value of mh)
Vh = sqrt(5) * Vn -----------------(4)

so velocity of helium atoms is nearly sqrt(5) or 2 times that of neon atoms,

similarly, momentum, P = m * V
ph = mh*Vh
Ph = 4 * Vh
Ph = 4 * sqrt(5) * Vn -----------(5)

also
Pn = 20 * Vn
Pn = 20 * Vh/sqrt(5)
Pn = (5/sqrt(5) ) * Ph --------------(6)   

momentum of neons atoms will be (5/sqrt(5)) or 2.5 times that of Heilium.

Collision merely depend upon the energy,which is given by

E = 0.5 * M * V^2

Therefore,
En = 0.5 * 20 * Vn^2 (Energy of neon atom)

Eh = 0.5 * 4 * Vh^2 (Energy of Helium atom)

Eh = 0.5 * 4 * 5 * Vn^2 (Using 4)
Eh = En

Energy will be same for both atoms,

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