13. perpendicular to a 0.90 Tuniform magHullu llllul is a) 0.17 b) 7.1 N/m c) 0.

Question

13. perpendicular to a 0.90 Tuniform magHullu llllul is a) 0.17 b) 7.1 N/m c) 0.14 N/m d) 5.8 N/m e) 7.3 N/m of the force on a 14. Determine the magnitude and direction fiel m/s horizontally to the east in a vertically upward magnetic a) south travelling115x1 of strength0AST. b) 1.2 x 1013 N, north c) 1.2 x 10 13 N, south d) 2.7 x10 13 N, south e) 5.6 x 10 14 N, north 65 A current. How strongisthe 5. Jumper cables used to start a stalled vehicle carry a one cable? magnetic field due to this current at a distance 4.5 cm from a) 3.5 x 103T b) 9.1 104T c) 2.9 x 104T

Explanation / Answer

Formula: F=qvB (sin)
q = charge of electron =1.69*10-19C
v = velocity = 7.75*105 m/s
B = magnetic field strength = 0.45T
= 90
sin =1

F = qvB = 1.6*10-19 x 7.75*105 x 0.45 = 5.58*10-14 N

By the right hand rule, the force must be directed to the North

so option E

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