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A shown in the figure, a charge q_1 = 1.00 muC is located at the origin and a ch

ID: 582569 • Letter: A

Question

A shown in the figure, a charge q_1 = 1.00 muC is located at the origin and a change q_2 = -6.00 muC is located at (0, 3.00) m. Find the total electric potential due to these charges at the point P, whose coordinates are (4.00, 0) m. Find the change in potential energy of the system of two charges plus a third charge q_3 = muC as the latter charge moves from infinity to point P. Find the change in potential energy of the system of two charges plus a third charge q_3 = 3.20 muC as the latter charge moves from infinity to point P. Assign U_1 = 0 for the system to the configuration in which the charge q_3 is at infinity. Evaluate the potential energy for the configuration in which the charge is at P: Substitute numerical values to evaluate DeltaU: there fore, because the potential energy of the system has decreased, an external agent has to do positive work to remove the charge from point P back to infinity. Find the total potential energy of the system of three charges in the configuration shown in Figure (b) in the example. Calculate the total potential energy as the sum of the potential energy contributions from each pair of interacting charges.

Explanation / Answer

Master it:
q1 = 1*10^-6 C
q2= -6*10^-6 C
q3=3.2*10^-6 C
r12 = 3m
r13=4 m
r23 = sqrt (3^2+4^2) = 5 m

U = K*[q1*q2/r12 + q1*q3/r13 + q2*q3/r23]
= (9*10^9)*[1*10^-6*-6*10^-6/3 + 1*10^-6*3.2*10^-6/4 + 3.2*10^-6*-6*10^-6/5]
= (9*10^9)*[ - 2*10^-12 + 8*10^-13 -3.84*10^-12]
=9*10^9 * (-5.04*10^-12)
= -0.04536 J

Answer: -0.04536 J

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