a refrigerator is operating at a COP of 0.98, which is 13% of the maximum COP th

Question

a refrigerator is operating at a COP of 0.98, which is 13% of the maximum COP theoretically possible. the temperature of the freezer compartment is -12 degrees Celsius. what is the temperature of the surrounding room.? a refrigerator is operating at a COP of 0.98, which is 13% of the maximum COP theoretically possible. the temperature of the freezer compartment is -12 degrees Celsius. what is the temperature of the surrounding room.? a refrigerator is operating at a COP of 0.98, which is 13% of the maximum COP theoretically possible. the temperature of the freezer compartment is -12 degrees Celsius. what is the temperature of the surrounding room.?

Explanation / Answer

maximum theoretical COP=0.98/0.13=7.5384

as we know, theoretically, maximum COP will be

COP(max)=Tcold/(Thot-Tcold)

here given that Tcold=-12 degree celcius=-12+273=261 kelvin

we have to find out Thot which is the surrounding temperature

hence 7.5384=261/(Thot-261)

==>Thot-261=34.622

==>Thot=295.62 K

=295.62-273=22.62 degree celcius

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