The three point charges +4.0 C, -5.0 C, and -9.0 C are placed on the x-axis at t

Question

The three point charges +4.0 C, -5.0 C, and -9.0 C are placed on the x-axis at the points x = 0 cm, x = 40 cm, and x = 120 cm, respectively. What is the x component of the electrostatic force on the -9.0 C charge due to the other two charges? (k = 1/40 = 9.0 × 109 N • m2/C2) The three point charges +4.0 C, -5.0 C, and -9.0 C are placed on the x-axis at the points x = 0 cm, x = 40 cm, and x = 120 cm, respectively. What is the x component of the electrostatic force on the -9.0 C charge due to the other two charges? (k = 1/40 = 9.0 × 109 N • m2/C2) 0.55 N -0.55 N -0.41 N 0.41 N 0.64 N

Explanation / Answer

Here ,

charge , q1 = 4 uC at x = 0 cm

charge , q2 = -5 uC at x = 40 cm

charge , q3 = -9 uC at x = 120 cm

x component of electrostatic force on -9 uC charge is F

F = 9*10^9 * 9 *10^-6 * (5 *10^-6/(1.2 - 0.4)^2 - 4 *10^-6/1.2^2 )

solving

F = 0.408 N

the x component of electrostatic force on -9 uC charge is 0.408 N

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