A parallel plate capacitor with plate separation of 4.0 cm has a plate area of 4

Question

A parallel plate capacitor with plate separation of 4.0 cm has a plate area of 4.0 times 10^-2 m^2. What is the capacitance of this capacitor with air between these plates? A parallel-plate capacitor has plates of area 0.80 m^2 separated by a distance of 3.0 mm. What is this capacitor's capacitance? A parallel-plate capacitor has plates of area 0.20 m^2 separated by a distance of 1.0mm What is this capacitor's capacitance? Three capacitors are connected as shown in What is the equivalent capacitance between points A and B?

Explanation / Answer

capacitance = C = eo*A/d

C = (8.9*10^-12*4*10^-2)/0.04 = 8.9*10^-12 F

option (A)

_______

(20)

C = (8.9*10^-12*0.8)/0.003 = 2.4*10^-9 F

option (B)

__________

21)

C = (8.9*10^-12*0.2)/0.001 = 1.8 nF

option (A)

_____________________

22)

C1 = 2 uF

C2 = 4 uF

C3 = 6 uF

C2 & C3 are in parallel

C23 = C2 + C3 = 10 uF

C1 & C23 are in series

Ceq = (C1*C23)/(C1+C23)

Ceq = (2*10)/(2+10) = 1.7 uF

option (E)

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