Two horizontal forces, vector F1 and vector F2, are acting on a box, but only ve

Question

Two horizontal forces, vector F1 and vector F2, are acting on a box, but only vector F1 is shown in the drawing. vector F2 can point either to the right or to the left. The box moves only along the x axis. There is no friction between the box and the surface. Suppose that vector F1 = +3.3 N and the mass of the box is 4.1 kg. Find the magnitude and direction of vector F2 when the acceleration of the box is the following.

(a) Find the magnitude and direction of vector F2 when the acceleration of the box is +4.3 m/s2. (Indicate the direction of the force by the sign of your answers.) vector F2 = (b)

Find the magnitude and direction of vector F2 when the acceleration of the box is -4.3 m/s2. (Indicate the direction of the force by the sign of your answers.) vector F2 = (c)

Find the magnitude and direction of vector F2 when the acceleration of the box is 0 m /s2. (Indicate the direction of the force by the sign of your answers.) vector F2 =

Explanation / Answer

M = 4.1 Kg
F1 = 3.3 i^ N

(a)
Acceleration a, = 4.3 m/s^2
Force = M*a
F = 4.1 * 4.3 N
F = 17.63 N

Magnitude of F2 = 17.63 - F1 = 17.63 - 3.3
F2 = 14.33 i^ N
Direction towards +ve X axis.

(b)
Acceleration a, = -4.3 m/s^2
Force = M*a
F = - 4.1 * 4.3 N
F = - 17.63 N

Magnitude of F2 = 17.63 + F1 = 17.63 + 3.3
|F2| = 20.93 N
Direction = -ve X axis.

F2^ = - 20.93 i^ N

(c)
Acceleration a, = 0 m/s^2
Force = M*a
F = 0 N

This means F2 is equal and opposite to F1.

Magnitude of F2 = 3.3 N
Direction of F2 = -ve X axis.

F2 = - 3.3 i^ N

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