A cameraman on a pickup truck is traveling westward at 23 km/h while he videotap
ID: 583150 • Letter: A
Question
A cameraman on a pickup truck is traveling westward at 23 km/h while he videotapes a cheetah that is moving westward 40 km/h faster than the truck. Suddenly, the cheetah stops, turns, and then run at 44 km/h eastward, as measured by a suddenly nervous crew member who stands alongside the cheetah's path. The change in the animal's velocity takes 1.8 s. What are the (a) magnitude and (b) direction of the animal’s acceleration according to the cameraman and the (c) magnitude and (d)direction according to the nervous crew member?
Explanation / Answer
Vc = - 23 km/h i^
Vch = - 63 km/h i^
Vch = 44 km/hr i^
1.8 s = 0.0005 hr
(a)
According to cameraman,
Vch = - 40 km/hr
Vchf = (44-23) km/hr = + 21 km/hr
a = (vchf - vch)/t
a = (21 + 40)/0.0005 km/hr^2
a = 122 * 10^3 km/hr^2
(b)
Direction, towards +ve x axis.
(c)
According to Crew Member,
a = (Vf - Vi)/t
a = (44 + 63) / 0.0005
a = 214 * 10^3 km/hr^2
(d)
Direction, towards +ve x axis.
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