Two capacitors C1 and C2 are connected to a voltage source as shown. Capacitor C

Question

Two capacitors C1 and C2 are connected to a voltage source as shown. Capacitor C2 has a larger capacitance than capacitor C1 i.e., C2 > C1 Incorrect The voltage drop across C1 is smaller than across C2. Incorrect The voltage drop across both capacitors is equal. Correct: The voltage drop across C2 is smaller than across C1. Correct: The charge is the same on both capacitors. Incorrect The charge on C2 is smaller than on C1. Incorrect The charge on C2 is larger than on C1. If C2=800 mu Fand C1=100 mu F, what is the total capacitance? If the voltage source has V = 9 Volts, what is the voltage drop delta V2 across capacitor C2?

Explanation / Answer

since both capaitors are in series so

1/Ceq=1/C1+1/C2

=1/800+1/100

Ceq=80uF

charge will remain same in capacitor un series so

so Qt=CqV

QT=80*9

=720uC

Q1=Q2=720uC

across c2 the voltage drop will be

V2=Q2/C2

=720uC/800uF

v2=0.9 V

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