Sam holds a lit match in front of a lens (f=30.0 cm)... (Need help on all 3 part

Question

Sam holds a lit match in front of a lens (f=30.0 cm)... (Need help on all 3 parts. Will rate high for quick, correct answers. See image below.)

Map dfab Sam holds a lit match in front of a lens (f= 30.0 cm). The distance between the match and the lens is so-45.0 cm Answer these three questions using three signifcant figures. Part A: Pick the selection that describes the characteristics of the image from the match. O O O O real and upside down real and erect virtual and upside down virtual and erect Part B: What is the value of the image distance? Number Si = c m Part C: If the flame is actually 1.500 cm tall, how tall is the image of the flame? (Enter your answer as a positive number.) Number cm

Explanation / Answer

so = object distance = 45 cm

f = focal length = 30 cm

si = image distance

Part A )

Real and upside down     Since the object distance is greater than the focal length.

Part B)

using the lens equation

1/f = 1/so + 1/si

1/30 = 1/45 + 1/si

si = 90 cm

Part c)

ho = object height = 1.5 cm

hi = image distance

Using the equation

hi/ho = - si/so

hi / 1.5 = - 90 / 45

hi = - 67.5 cm

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