1. Mass of NaOH: 2.07g Mass of solution: 100g Final temperature: 27.98 degrees c

Question

1. Mass of NaOH: 2.07g Mass of solution: 100g Final temperature: 27.98 degrees celcius Initial temp: 19.3 degrees celcius Change in temp: 8.68 degrees celcius

Delta H/mol= ?

2. Mass of solution: 100g Final temperature: 23.57 degrees celcius Initial temp: 18.64 degrees celcius Change in temp: 4.93 degrees celcius
Delta H/mol ? 1. Mass of NaOH: 2.07g Mass of solution: 100g Final temperature: 27.98 degrees celcius Initial temp: 19.3 degrees celcius Change in temp: 8.68 degrees celcius

Delta H/mol= ?

2. Mass of solution: 100g Final temperature: 23.57 degrees celcius Initial temp: 18.64 degrees celcius Change in temp: 4.93 degrees celcius
Delta H/mol ? Mass of NaOH: 2.07g Mass of solution: 100g Final temperature: 27.98 degrees celcius Initial temp: 19.3 degrees celcius Change in temp: 8.68 degrees celcius

Delta H/mol= ?

2. Mass of solution: 100g Final temperature: 27.98 degrees celcius Initial temp: 19.3 degrees celcius Change in temp: 8.68 degrees celcius

Delta H/mol= ?

2. Mass of solution: 100g Final temperature: 23.57 degrees celcius Initial temp: 18.64 degrees celcius Change in temp: 4.93 degrees celcius Mass of solution: 100g Final temperature: 23.57 degrees celcius Initial temp: 18.64 degrees celcius Change in temp: 4.93 degrees celcius
Delta H/mol ?

Explanation / Answer

1)

Mass of NaOH = 2.07g

Mass of solution = 100 g

Change in temp dT = 8.68 oC

Q = m Cp dT

= 100 x 4.184 x 8.68

Q = 3631.7 J

moles of NaoH = 2.07 / 40 = 0.05175

delta H = - Q / n = - 3631.7 x 10^-3 / 0.05175

delta H = - 70.2 kJ/mol

2)

Q = 100 x 4.184 x 4.93 = 2062.7 J

delta H = - 2062.7 x 10^-3 / 0.05175

           = -39.9 kJ/mol

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