I found the answer to the first two, i just need help with the last one Two ante

Question

I found the answer to the first two, i just need help with the last one

Two antennas located at points A and B are broadcasting radio waves of frequency 98.0 MHz, perfectly in phase with each other. The two antennas are separated by a distance d= 12.40 m. An observer, P, is located on the x axis, a distance x= 78.0 m from antenna A, so that APB forms a right triangle with PB as hypotenuse. What is the phase difference between the waves arriving at P from antennas A and B?
Answer: 2.101 Radians

Now observer P walks along the x axis toward antenna A. What is P's distance from A when he first observes fully destructive interference between the two waves?
Answer: 49.6m

If observer P continues walking until he reaches antenna A, at how many places along the x axis (including the place you found in the previous problem) will he detect minima in the radio signal, due to destructive interference?
NEED ANSWER:
When P was far away from A, the path length difference was small. When Parrives at A, the path length difference equals d. At how many places between was the condition for destructive interference satisfied?

Explanation / Answer

= 3*10^8/98*10^6= 3.061m

n=2: ( n+1/2 )=3.061*2.5= 7.653m

x^2+153.76= (x+7.653)^2
x^2+153.76= x^2+15.306x+58.568
15.306x=95.192
x= 6.21 m

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