It is possible to shoot an arrow at a speed as high as 113 m/s. If friction is n

Question

It is possible to shoot an arrow at a speed as high as 113 m/s. If friction is neglected, how high would an arrow launched at this speed rise if shot straight up? How long would the arrow be in the air? A certain automobile manufacturer claims that its deluxe sports car will accelerate from rest to a speed of 49.0 m/s in 8.80 s. Determine the average acceleration of the car. Assume that the car moves with constant acceleration. Find the distance the car travels in the first 8.80 s. What is the speed of the car 10.0 s after it begins its motion if it continues to move with the same acceleration?

Explanation / Answer

Given,

v = 113 m/s

a)Let this height be H.

We know from the equation of motion that,

v2 = u2 + 2 a S

In our case, v = 113 m/s ; u = 0 ; a = g = 9.8 m/s2 and S = H

2 x 9.8 x H = 113 x 113

H = 651.48 m

Hence, H = 651.48 m

b)Let T be the required time

from first equation of motion we know that,

v = u + at

In our case, u = 113 m/s ; v = 0 and a = -g = -9.8 m/s2

113 - 9.8 t = 0

t = 11.53 sec

Its the time for one side, So the total time for which it will be in air will be:

T = 2t = 2 x 11.53 s = 23.06 s

Hence, T = 23.06 s

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