The figure below shows a cold package of hot dogs sliding rightward across a fri

Question

The figure below shows a cold package of hot dogs sliding rightward across a frictionless floor through a dist?

The figure below shows a cold package of hot dogs sliding rightward across a frictionless floor through a distance d = 20.0 cm while three forces are applied to it. Two of the forces are horizontal and have the magnitudes F1 = 5.00 N and F2 = 1.00 N; the third force is angled down by = 65

.0° and has the magnitude F3 = 4.00 N. 

for the 20cm displacement. what is the net work done of the package by the 3 applied forces, the gravitational force on the package and the normal force on package?

If the package has a mass of 2.2 kg and an initial kinetic energy of 0, what is its speed at the end of the displacement?

Explanation / Answer

The work is only done by the forces along which displacement takes place.

Hence Finding the net force in horizontal direction

Fh = F1 - F2 + F3cos (65) = 5 -1 + 4* cos (65) = 5.69 N

hence the work done is

W = Fd

W= 5.69* .2 = 1.138 J

The work done by gravity and normal force is 0

This work is stored as kinetic energy

W = 1/2 mv^2 = 1.138 J

v = 1.017 ms-1

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