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14) Here are the measured hydrogen and helium masses: 1H(aka hydrogen): m1H=1.00

ID: 584461 • Letter: 1

Question



14) Here are the measured hydrogen and helium masses:
1H(aka hydrogen): m1H=1.007825u=mp+me (recall that standard hydrogen has no neutrons)

2H(aka deuterium): m2H=2.014102u
3H(aka tritium): m3H=3.016049u
3He: m3He=3.016030u
4He: m4He=4.002603u

a) obtain the binding energy of a deterium atom.
b) obtain the annihilation energy of a deterium atom.
c) write a nuclear reaction in which a deterium atom and tritium atom are transformed into a 4He atom.
d) For the reaction you gave
in (c), obtain the released energy in this reaction

please help asap thanks!
3He: m3He=3.

bl What is the energy released? [cl You measure the kinetic enerey of the alpha (d) Obtain the speed of the daughter [e) Obtain the kinetic energy of the daughter. 13) You have 3 particles, an electron, a prator (1.5x10' ev, or 0.35 Mev) obtain the marnentu (a) electron p and (bl proton p and c) gamma p and 14) Here are the measured hydrogen and heli 'H laka hydrogen): H (aka deuterium): ".,-2.04112 , m-100825u II [aka tritium):3149/ H (aka tritium): -3.0104 He , ll,-3.01603(N He 3.01800 a) Obtain the binding energy of a deuteriur (b) Obtain the annihilation energy of a deut which a deut (c), obtain t (c) Write a nuclear re 2.3x10

Explanation / Answer

a)

Binding Energy is 2.014102*931.5 = 1876.136 MeV

c)

2H+3H -->4He+1n

d)

Energy released is M(2H+3H ) -M(4He+1n)

Energy Released is ((2.014102+3.016049)-(4.002603+1.0086654))*931.5 MeV

Energy Released is is 17.589 MeV

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