The graph shows the displacement from equilibrium of a mass-spring system as a f
ID: 585517 • Letter: T
Question
The graph shows the displacement from equilibrium of a mass-spring system as a function of time after the vertically hanging system was set in motion at time t =0. Assume that the units of time are seconds, and the units of displacement are centimeters. The first f-intercept is (0.75,0) and the first minimum has coordinates (1.75,-4). What is the period T of the periodic motion? T = seconds What is the frequency/in Hertz? What is the angular frequency w; in radians/second? F = Hertz W= radians/second Determine the amplitude A and the phase angle gama (in radians), and express the displacement in the form y(t) = A cos(wt - gama), with y in meters. y(t) = meters With what initial displacement y(0) and initial velocity y '(0) was the system set into motion? Y'(0) = meters y'(0) = meters/secondExplanation / Answer
a)
1 wavelength of graph is spread across 4s
So,
T = 4 s
b)
f = 1/T
= 1/4
= 0.25 hZ
w = 2*pi*f
= 2*pi*0.25
=1.57 rad/s
d)
Amplitude, A = 4 m
phase = -0.2 s
= -0.2*2*pi/T rad
= -0.2*2*pi/4 rad
= -0.314 rad
y(t) = A*cos (wt-phase)
= 4* cos (1.57*t +0.314)
e)
y(t) = 4* cos (1.57*t +0.314)
y(0) = 4* cos (1.57*0 +0.314)
= 4* cos (0.314)
= 3.8 m
y(t) = 4* cos (1.57*t +0.314)
y'(t) = - 4*1.57* sin (1.57*t +0.314)
y'(0) = - 4*1.57* sin (0.314)
= -1.94 m/s
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