When a train\'s velocity is 12.0 m/s eastward, raindrops that are falling vertic

Question

When a train's velocity is 12.0 m/s eastward, raindrops that are falling vertically with respect to the earth make traces that are inclined 30.0 to the vertical on the windows of the train.

Part A

What is the horizontal component of a drop's velocity with respect to the earth?

Part B

What is the horizontal component of a drop's velocity with respect to the train?

Part C

What is the magnitude of the velocity of the raindrop with respect to the earth?

Part D

What is the magnitude of the velocity of the raindrop with respect to the train?

Explanation / Answer

A. Zero. You are told that its falling vertically wrt the earth so it can have no component in the horizontal direction.

B. 12 m/s West . Just the reverse of the trains velocity.

C. Tan 30 = Vhoriz / Vdown so Vdown = Vhoriz / tan 30 = 20.78 m/s

D. Vel raindrop wrt train = sq.rt. ( Vhoriz^2 + Vdown^2 )
= sqrt ( 12^2 + 20.78^2 ) = 24 m/s

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.