Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

The acceleration is the ratio of the net force divided by the total mass. Calcul

ID: 585799 • Letter: T

Question

The acceleration is the ratio of the net force divided by the total mass. Calculate the net force, Fnet, and record it below.

Procedure 1 For Run #1 use the arrangement described above one 20g mass on the mass hanger Weigh the cart and the mass hanger with a 20g mass, and enter these values in Table 1 2. Pull the cart about 25 cm from the endstop. Click Start. Release the cart. Stop the cart before it hits the pulley and click Stop 3. For Run #2, add a 250-g mass to the cart. Weigh the total mass of the cart plus the extra mass and record this value in Table 1 4. For Run #3, add a second 250-g mass to the cart. Weigh the total mass of the cart plus the two extra masses and record this value in Table 1. Table 1 Mass (kg) 0.496 0.023 0.771 1.011 Item Run #1: Mass of the cart Run #1: Total mass of the hanger and 20-g mass | Run #2: Total mass of cart plus one 250-g mass | Run #3: Total mass of cart plus two 250-g masses! Calculations 1. The acceleration is the ratio of the net force divided by the total mass. Calculate the net force, Fnet, and record it below e, Fnet

Explanation / Answer

a = m_hanging * g / ( m_cart + m_hangign)

1 )

a = 20 * 10^-3 * 9.8 / 516 x 10^-3

a = 0.3798 = 0.38 m/s^2

Fnet = ma = 0.196 N

2 )

a = 20 * 10^-3 x 9.8 / 0.043

a = 4.56

Fnet = 4.56 * 0.043 = 0.196

3 )

a = 20 * 10^-3 x 9.8 / 0.771

Fnet = ma

Fnet = 0.196 N

4 )

a = 20 x 10^-3 * 9.8 / 1.011

Fnet = ma

Fnet = 0.196

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote