determine the total work done by all forces after the crate has moved the distan

Question

determine the total work done by all forces after the crate has moved the distance D:

The crate moves up the incline a distance d = 5 ft due to the action of the constant force P-110 lb. The weight of the crate is W = 68 lb and the spring with constant k = 10 lb/ft is unstretched before the crate starts moving. Friction between the crate and the incline is negligible and the angle between the force P and the surface on which the crate slides is -30°. Letting 30°, determine the total work done by all forces after the crate has moved the distance d 1-2 ft-lb

Explanation / Answer

net force on the crate is

Fnet = Pcos(30 degree) - [wsin(30 degree) + kx ] = 110*0.866 - [68*0.5 + 10*5] = 11.26 lb

so workdone by Fnet is   W = Fnet*d = 11.26*5 = 56.3 ft-lb

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