We will learn shortly that the particle carrying electric charge qq experiences

Question

We will learn shortly that the particle carrying electric charge qq experiences electrical force when moving through the region of space filled with electric field E. The force it experience is simply F =qE. In this problem we will consider a very simple case. Electric field points along the y (vertical axis) of the coordinate system that has the x (horizontal axis parallel to Earth ground. It does not matter how this is accomplished but we assume that the electric field is more or less constant, directed towards the ground (x-axis) and has magnitude of E=600 N/C. The electrical charge is positive and has magnitude of q=1.2×10^8 C. (C is an acronym for the unit of electrical charge called Coulomb).

Imagine that somehow the charge is held at rest and then released.

How long it will take the charge to hit the ground if initially is was at an altitude of 100 m?

With what speed will the charge hit the ground?

If the body carrying the charge has mass of 1×10^3 kg compare the strength ef electrical and gravitational forces on the body.

If we could somehow turnoff the electric field and then repeat the experiment, how long will it take the body to hit ground?

With what speed it will hit the ground?

Please show work

Explanation / Answer

Fy = E*q

ay = Fy/m

ay = (600*1.2*10^-8)/(1*10^-3) = 0.0072 m/s^2

along vertical

y = voy*t + 0.5*ay*t^2

100 = 0.5*0.0072*t^2

t = 167 s

+++++++++++

v = sqrt(2*a*y) = sqrt(2*0.0072*100) = 1.2 m/s

______________________-

Fg = mg

Fe/Fg = (600*1.2*10^-8)/(10^-3*9.8) = 0.000735

--------------

t = sqrt(2y/g)

t = sqrt(2*100/9.8) =4.52 s

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