While leaning out a window that is 6.0 m above the ground, you drop a 0.60-kg ba
ID: 586673 • Letter: W
Question
While leaning out a window that is 6.0 m above the ground, you drop a 0.60-kg basketball to a friend at ground level. Your friend catches the ball at a height of 1.3 m above the ground. Determine the following. (a) the amount of work done by the force of gravity (b) the gravitational potential energy of the ball, relative to the ground when it is released (c) the gravitational potential energy of the ball, relative to the ground when it is caught (d) the ratio of the change (PEf PE0) in the ball's gravitational potential energy to the work done on the ball by the force of gravity
Explanation / Answer
(a)
Work done by Force of Gravity = m*g*h
Work done by Force of Gravity = 0.6*9.8*(6.0-1.3) J
Work done by Force of Gravity = 27.64 J
(b)
Gravitational potential energy of the ball when it is released, = m*g*h
Gravitational potential energy of the ball when it is released, = 0.6*9.8*6.0 J
Gravitational potential energy of the ball when it is released, = 35.28 J
(c)
Gravitational potential energy of the ball when it is caught, = m*g*1.9
Gravitational potential energy of the ball when it is caught, = 0.6*9.8*1.3 J
Gravitational potential energy of the ball when it is caught, = 7.644 J
(d)
Ratio = 1
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