1a. A sample of argon gas at a pressure of 0.824 atm and a temperature of 26.2 °

Question

1a. A sample of argon gas at a pressure of 0.824 atm and a temperature of 26.2 °C, occupies a volume of 10.4 liters. If the gas is allowed to expand at constant temperature to a volume of 14.6 liters, the pressure of the gas sample will be___________ atm?

1b. A sample of methane gas at a pressure of 0.832 atm and a temperature of 29.9 °C, occupies a volume of 553 mL. If the gas is compressed at constant temperature until its pressure is 1.05 atm, the volume of the gas sample will be_____________ mL.

Explanation / Answer

For ideal gas

PV = nRT

R is a constant and for a closed chamber n is also constant

PV/T = nR = constant for closed chamber

1a)

0.824 atm x 10.4 L / T = 14.6L x P/T

as Temperature is constant , I kept it as T as it will cancel out from both side

P = 0.587 atm

b)

this one is also at constant temperature and hence we can remove T as it is common both side

PV = constant

0.832 atm x 553 L = 1.05 atm x V

V = 438.187 mL

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.