11/26/2017 11:5s PM 93/1011/25/2017 12:45 PM PnntCalculator-Periodic Table Grade

Question

11/26/2017 11:5s PM 93/1011/25/2017 12:45 PM PnntCalculator-Periodic Table Gradebook estion 13 or 15 Incorrect Tutorial lesson Mapo General Chemistry 4th Edition University Science Books presented by Saping Learning . The voltage generated by the zinc concentration cell described by Zn(s)Zn2(aq, 0.100 M)lIZn2(aq, ? M)|Zn(s) is 12.0 mV at 25 . Calculate the concentration of the Zn2+(aq) ion at the cathode. Number 0.276 Previous Give Up & View Solution # Try Again O Next Exit privacy policy terms of use contact

Explanation / Answer

Number of electron being transferred in balanced reaction is 2

So, n = 2

This is concentration cell.

So, Eo = 0 V

we have below equation to be used:

E = Eo - (0.0592/n) log {[Zn2+]^1/[Zn2+]^1}

0.012 = 0.0 - (0.0592/2) log (0.1^1/[Zn2+]^1)

log (0.1^1/[Zn2+]^1) = -0.4054

(0.1^1/[Zn2+]^1) = 0.3932

[Zn2+] = 0.254

Answer: 0.254 M

Feel free to comment below if you have any doubts or if this answer do not work. I will edit it if you let me know

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