Type of Food sample 109.01 A 301 Mass of aluminum can and water Mass of aluminum

Question

Type of Food sample 109.01 A 301 Mass of aluminum can and water Mass of aluminum can Mass of food Final temperature of water Initial temperature of water B.1 B.2 B.3 B.4 Mass of food remaining Calculations B.5 Mass of water B.6 Temperature change for water B.7, Heat gain (calories) of water 1 7504 4.13 15°0 (a) 123 le .45 cal (1315-J (Show calculations) b. Heat gain (kilocalories) of water c Heat loss (calories) of food sample dHeat loss (kilocalories) of food sample lories) of water 1.331 Kcal l)- 11) (A) B.8 Mass of food undergoing combustion -d1314 - B.9 Caloric value (kcal/g) of food sample Show calculations

Explanation / Answer

Analysis of food material

B5. mass of water = 89.132 g

B6. dT = 15 oC

B7. Heat gain of water

a. q = mCpdT

       = 89.132 x 4.18 x 15/4.18 = 1337 cal

b. heat gain = 1.337 kcal

c. heat loss of food sample = 1337 cal

d. heat loss of food = 1.337 kcal

B8. mass of food = 2.121 g

B9. caloric value of food sample = 1.337 kcal/2.121 g = 0.630 kcal/g

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