Flat tail is dominant to fuzzy tail and having teeth is dominant to toothless. G

Question

Flat tail is dominant to fuzzy tail and having teeth is dominant to toothless. Give the phenotypic ratios resulting from a cross between two parents, both heterozygous for each gene.

5/16 flat tail and with teeth, 4/16 flat tail and without teeth, 4/16 fuzzy tail and with teeth, 3/16 fuzzy tail and without teeth

9/16 flat tail and with teeth, 4/16 flat tail and without teeth, 2/16 fuzzy tail and with teeth, 1/16 fuzzy tail and without teeth

8/16 flat tail and with teeth, 3/16 flat tail and without teeth, 3/16 fuzzy tail and with teeth, 2/16 fuzzy tail and without teeth

4/16 flat tail and with teeth, 4/16 flat tail and without teeth, 4/16 fuzzy tail and with teeth, 4/16 fuzzy tail and without teeth

9/16 flat tail and with teeth, 3/16 flat tail and without teeth, 3/16 fuzzy tail and with teeth, 1/16 fuzzy tail and without teeth

A.

5/16 flat tail and with teeth, 4/16 flat tail and without teeth, 4/16 fuzzy tail and with teeth, 3/16 fuzzy tail and without teeth

B.

9/16 flat tail and with teeth, 4/16 flat tail and without teeth, 2/16 fuzzy tail and with teeth, 1/16 fuzzy tail and without teeth

C.

8/16 flat tail and with teeth, 3/16 flat tail and without teeth, 3/16 fuzzy tail and with teeth, 2/16 fuzzy tail and without teeth

D.

4/16 flat tail and with teeth, 4/16 flat tail and without teeth, 4/16 fuzzy tail and with teeth, 4/16 fuzzy tail and without teeth

E.

9/16 flat tail and with teeth, 3/16 flat tail and without teeth, 3/16 fuzzy tail and with teeth, 1/16 fuzzy tail and without teeth

Explanation / Answer

Heterozygous parents: Ff x Tt

The cross results in dihybrid cross ratio of 9:3:3:1; 9/16 flat tail and with teeth, 3/16 flat tail and without teeth, 3/16 fuzzy tail and with teeth, 1/16 fuzzy tail and without teeth. Therefore the option E is correct.

Male/female F f T t F FF Ff FT Ft f Ff ff fT ft T FT fT TT Tt t Ft ft Tt tt

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