This is a Numeric Entry question/It is worth 1 point / You have unlimited attemp

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This is a Numeric Entry question/It is worth 1 point / You have unlimited attempts / There is no attempt penalty 10 Question (1 point) a See page 896 The oxidation of HNO2 to NO3 in acid solution is a 4-electron transfer reaction described by the following equation: 2HNO2(aq) +02(g)-> 2NO (aq) +2H+(aq) Edell=0.289 V If the reaction at 298 K is in equililbrium with air (Po2-0.300 atm) at pH 6.00, what is the ratio of INOs1to [HNO2)? 1st attempt lai See Periodic Table See Hint Write your answer in scientific notation containing three significant figures. SUBMIT ANSWER 6

Explanation / Answer

G° = -nFE°

= - (4 × 96485C/mol × 0.289V)

= -111536J/mol

G°= - RTlnK

logK = -G°/2.303RT

= -(-111536(J/mol) /(2.303×8.314(J/Kmol)×298K)

= 19.55

K = 3.55×10^19

K = [NO3-]2[H+]2/[HNO2]^2[O2]

pH = 6

-log[H+] = 6

[ H+ ] = 1×10^-6M

n/V= P/RT

= 0.300atm/0.082057( L atm / mol K )×298K

= 0.0123M

[NO3-]^2 / [HNO2]^2= 3.55×10^19[O2]/[H+]^2

= 3.55 × 10^19 M× 0.0123M/(1×10^-6M)^2

   = 4.37× 10^29

[ NO3-] / [HNO2] = 6.61×10^14

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