LABORATORT 27 5. A voltaic cell is constructed by immersing a strip of lead meta
ID: 588153 • Letter: L
Question
LABORATORT 27 5. A voltaic cell is constructed by immersing a strip of lead metal in a 1.0MPb(NO) solution and a strip of cadmium metal in a 1.0 M Cd(NO), solution. The circui is completed by a wire and a salt bridge in the usual way, Anawer questions a-e a. Write the balanced overall net-ionic cell reaction. b. What is the cell potential for the voltaic cell described above c. Write the balanced net-ionic half-reaction that is occurring at the cathode. d. Write the balanced net-ionic half-reaction that is occurring at the anode. What would be the potential of the cell if it was modified to use a 0.10 M Pb(NO), solution and a 0.20 M Cd(NO), solution instead e.Explanation / Answer
at anode
Cd(s) --------------------> Cd^2+ (aq) + 2e^- oxidation half reaction
at cathode
Pb^2+ (aq) +2e^- ----------------> pb(s) reduction half reaction
Cd(s) --------------------> Cd^2+ (aq) + 2e^-
Pb^2+ (aq) +2e^- ----------------> Pb(s)
---------------------------------------------------------------------------
Cd(s) + Pb^2+ (aq) ------------> Cd^2+ (aq) + Pb(s) net overall reaction
Cd(s) --------------------> Cd^2+ (aq) + 2e^- E0 = 0.40v
Pb^2+ (aq) +2e^- ----------------> Pb(s) E0 = -0.13v
---------------------------------------------------------------------------
Cd(s) + Pb^2+ (aq) ------------> Cd^2+ (aq) + Pb(s) E0 cell = 0.27v
n= 2
E cell = E0cell - 0.0592/n logQ
= 0.27 -0.0592/2 log[Cd^2+]/[Pb^2+]
= 0.27-0.0296log0.1/0.2
=0.27-0.0296*-0.3010
= 0.2789v >>>answer
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.