A compound which contains only carbon, hydrogen, and sulfur is burned in oxygen

Question

A compound which contains only carbon, hydrogen, and sulfur is burned in oxygen under such conditions that the individual volumes of the reactants and products can be measured at the same temperature and pressure. It is found that 3 volumes of the compound react with oxygen to yield 3 volumes of carbon dioxide, 3 volumes of sulfur dioxide, and 6 volumes of water vapor. What volume of oxygen is required for the combustion? What is the formula of the compound? Is this an empirical formula or a molecular formula? 5.

Explanation / Answer

Given that 3 volumes of compound reacts with oxygen to form 3 volumes of CO2 and 3 volumes of SO2 and 6 volumes of H2O.

The unbalanced chemical equation as follows:

3 CHS + O2 ----> 3 CO2 + 3 SO2 + 6 H2O

Reactant side and products side number of Carbons and sulfur atoms are equal.

To balance the hydrogen atoms take subscript 4 at hydrogen.

And take coefficient 9 before O2.

Hence balanced chemical equation as follows

3CH4S + 9 O2 -------> 3CO2 + 3 SO2 + 6 H2O

Hence volume of oxygen is 9.

Formula of the compound is CH4S.

This is molecular formula of methane thiol. (CH3SH).

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