For Practice 6.10 with feedback You may want to reference (paes 247-251) Section

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For Practice 6.10 with feedback You may want to reference (paes 247-251) Section 6.9 while completing this problem. Standard thermodynamic quantities for selected substances at 25 C Part A Enter the equation for the formation of RbCl(s) from lts respective elements in their standard states Express your answer as a chemical equation. Identify all of the phases in your answer Substance Rb(s) Rb g) CKE) Cl2(g) RbCl(s) Pb(s) Pb(g) Pb(NO,)2(s) N(g) N2 (g) O(g) 02(g) O3(g) AHf (kJ/mol) 0.0 80.9 121.3 0.0 -435.4 0.0 195.2 -451.9 472.7 0.0 249.2 0.0 142.7 2Rb(s) Cl2 (g)-2RbCl(s) Submit My Answers Give Up Correct Some nonmetals exist as diatomic gas molecules, and chlorine is one of those elements Part B What is the value of H tor the formation of 1 mol of RbCl(s)? Express the energy to four significant figures and include the appropriate units. kJ mol AHP690.6 Submit Incorrect; One attempt remaining; Try Again Part C Enter the chemical equation for the formation of Pb(NO2(s) from its respective elements in their standard states. Express your answer as a chemical equation. Identify all of the phases in your answer Submit My Answers dive U Incorrect; Try Again; 9 attempts remaining

Explanation / Answer

Answer:

Part A: The balanced equation is

2 Rb (s) + Cl2 (g) ----> 2 RbCl (s)

Part B:

delta H°f of a reaction is difference between sum of deltaH of products-sum of deltaH of reactants

delta H°f =2xdelta H°(RbCl)-[2xdelta H°f (Rb)+delta H°f (Cl2)]

Given delta H°f (Rb) (s)=0

delta H°f (Cl2) (g)=0

delta H°f (HgCl) (s)=-435.4 kJ/mol

delta H°f =2x-435.4 kJ/mol-[2x0+0]=-870.8 kJ/mol.

delta H°f =-870.8 kJ/mol.

Part C:

The balanced equation for the formation of Pb(NO3)2 is

Pb + N2 + 3O2 ------>Pb(NO3)2

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